python 해당시간에 특정작업실행

오전 8시 30분에서 오후 8시 30분까지 30초 인터벌로 TaskA 의 특정작업실행하기

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# -*- coding: utf-8 -*- ''' Created on 2018. 9. 4.   @author: bhm ''' from datetime import time, datetime import threading   class syncTask:     def __init__(self):         pass       def TaskA(self):         morning = time(8, 30)       # 시각 객체         evening = time(20, 30)          now = datetime.now().time()       # 일시 객체         dt = datetime.now()         print dt                   if morning <= now and evening > now:             print morning             print now             print evening             print '작동시작'         else:             print morning             print now             print evening             print '동작끝'                 print('sync Function OK (%s)' % dt +'\n')         threading.Timer(10, self.TaskA).start()           def main():     at = syncTask()     at.TaskA()   if __name__ == '__main__':     main()